Question: What is the electric flux through a closed surface that is enclosed by an electric dipole?

If it is a closed (Gaussian) surface which encloses the dipole, and there are no other charges within the surface, the flux is zero.

When electric dipole is enclosed in a closed surface then electric flux passing through the surface is not zero?

Assertion : If a dipole is enclosed by a surface, then according to Gauss’s law, electric flux linked with it will be zero. <br> Reason : The charge enclosed by a surface is zero.

What is the electric flux through a Gaussian surface of Area A enclosing an electric dipole where each charge has magnitude Q?

A pair of equal and opposite charges q and -q separated​ by 2d constitutes an electric dipole with moment p = 2qd. If the Gaussian surface encloses an electric dipole and no other charges, the net charge is zero. Hence the flux through the surface is zero.

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What is electric flux through a closed surface?

According to Gauss’s law, the flux of the electric field →E through any closed surface, also called a Gaussian surface, is equal to the net charge enclosed (qenc) divided by the permittivity of free space (ϵ0): ΦClosedSurface=qencϵ0.

Is the flux through a closed surface always zero?

The flux of a vector field through a closed surface is always zero if there is no source or sink of the vector field in the volume enclosed by the surface. … The flux of a electric field through a closed surface is always zero if there is no net charge in the volume enclosed by the surface.

Why is electric field inside a sphere zero?

since all the charge is distributed on the surface of the spherical shell so according to Gauss law there will not be any electric flux inside the spherical shell, because the charge inclosed by the spherical shell is zero, so there will not be any electric field present inside the spherical shell.

How do you find electric flux through a surface?

The Electric Flux through a surface A is equal to the dot product of the electric field and area vectors E and A. The dot product of two vectors is equal to the product of their respective magnitudes multiplied by the cosine of the angle between them.

When an electric dipole is held at an angle?

Answer: the forces experienced by the 2 charges constituting the electric dipole when placed in an uniform external electric field are equal and opposite in nature, the net force on the dipole is zero. No torque act on the dipole when the moment of electric dipole is parallel to the electric field.

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Why electric flux is zero in a closed surface?

Gauss’s law tells us that the electric flux through a closed surface is proportional to the net charge enclosed by the surface. Thus, the electric flux through the closed surface is zero only when the net charge enclosed by the surface is zero.

What will be the value of electric flux when an electric Diple placed into a closed surface?

Yes if a dipole is kept in a closed surface the net electric flux is . as in a dipole the two charges are equal in magnitude so the associated flux would be equal in magnitude but opposite in direction so the flux leaving is negative.

Is a Plane a closed surface?

The two-dimensional sphere, the two-dimensional torus, and the real projective plane are examples of closed surfaces.

What will be the flux of a box with no charge in it?

so there is no electric flux into or out of the box. In Fig. 22.3b, one positive and one negative point charge of equal magnitude are enclosed within the box, so the net charge inside the box is zero. … Hence there is no net electric flux into or out of the box.

Can a free charge Cannot be present inside a closed surface?

Nope! There is a theorem called Gauss’ theorem, which states that the flux of across a surface , is proportional to the amount of net charge inside the volume enclosed by .

How do you know if flux is positive or negative?

Flux: The flow across a surface

  1. When the field vectors are going the same direction as the vectors normal to the surface, the flux is positive.
  2. When the field vectors are going the opposite direction as the vectors normal to the surface, the flux is negative.
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